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#04f242a1-e15d-4e66-a049-6fb345491b40简单解答题等差数列的概念与通项数列

26.已知正项数列{an}\{a_{n}\},其前nn项和SnS_{n}满足an(2Snan)=1(nN)a_{n}(2S_{n}-a_{n})=1(n\in N*)
(1)求证:数列{Sn2}\{S_{n}^{2}\}是等差数列,并求出SnS_{n}的表达式;
(2)数列{an}\{a_{n}\}中是否存在连续三项aka_{k}ak+1a_{k+1}ak+2a_{k+2},使得1ak\frac{1}{a_k}1ak+1\frac{1}{a_{k+1}}1ak+2\frac{1}{a_{k+2}}构成等差数列?请说明理由.