23.如图所示,函数y=f(x)y=f(x)y=f(x)的图象是圆心在点(1,0)(1,0)(1,0),半径为1的两段圆弧,则不等式f(x)<f(2−x)+xf(x)<f(2-x)+xf(x)<f(2−x)+x的解集是[ ]{.underline}(0,1)⋃(85,2]({0,1})\bigcup ({\frac{8}{5},2}](0,1)⋃(58,2][ ]{.underline}.