23. 已知函数f(x)={ex,x⩽0∣lnx∣,x>0f(x)=\left\{{\left.\begin{array}{l}{{e^x},x\leqslant 0}\\ {\vert {lnx}\vert ,x>0}\end{array}\right.}\right.f(x)={ex,x⩽0∣lnx∣,x>0，则函数F(x)=f[f(x)]−1e2f(x)−1F(x)=f[{f(x)}]-\frac{1}{e^2}f(x)-1F(x)=f[f(x)]−e21f(x)−1的零点个数为((( )))