17.(2023•河南模拟)已知函数f(x)=a(x2−x)−lnxxf(x)=a({{x^2}-x})-\frac{lnx}{x}f(x)=a(x2−x)−xlnx,若不等式f(x)<0f(x)<0f(x)<0有且仅有1个整数解,则实数aaa的取值范围为 ___[ln318,ln24)[{\frac{ln3}{18},\frac{ln2}{4}})[18ln3,4ln2)___.