9．已知函数f(x)={2∣x∣,x⩽0∣lnx∣,x>0f(x)=\left\{{\left.\begin{array}{l}{{2^{\vert x\vert }},x\leqslant 0}\\ {\vert {lnx}\vert ,x>0}\end{array}\right.}\right.f(x)={2∣x∣,x⩽0∣lnx∣,x>0，则函数g(x)=f2(x)−3f(x)+2g(x)=f^{2}(x)-3f(x)+2g(x)=f2(x)−3f(x)+2零点的个数是 [ 6 ]．