9.在ΔABC\Delta ABCΔABC中,AB=2AC=2AB=2AC=2AB=2AC=2,PPP,QQQ为线段BCBCBC上的点,且BP→=PQ→=QC→\overrightarrow{BP}=\overrightarrow{PQ}=\overrightarrow{QC}BP=PQ=QC.若AP→⋅AQ→=59\overrightarrow{AP}\cdot \overrightarrow{AQ}=\frac{5}{9}AP⋅AQ=95,则∠BAC=(\angle BAC=(∠BAC=( )))