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#2cd456cc-48f7-46c0-bb0e-818dfb316bb6简单解答题等差数列的概念与通项数列

20. 已知数列{an}\{a_{n}\}是等差数列,且a2=25a_{2}=-252a3+a5=502a_{3}+a_{5}=-50
(1)求{an}\{a_{n}\}的通项公式;
(2)若数列{an}\{a_{n}\}的前nn项和为SnS_{n},求SnS_{n}的最小值及取得最小值时nn的值.