8.已知等差数列{an}\{a_{n}\}{an}中的各项均大于0,且3a32+a1+a5=163{a}_{3}^{2}+a_{1}+a_{5}=163a32+a1+a5=16,则a3a1−a11a3\frac{a_3}{a_1}-\frac{a_{11}}{a_3}a1a3−a3a11的最小值为((( )))