33．已知函数$f(x)=\left\{\begin{array}{l}{-\frac{1}{2}{x}^{2}+3,x<2,}\\ {lo{g}_{2}x,x\geqslant 2,}\end{array}\right.$若函数$g(x)=f^{2}(x)-(2m+1)f(x)+2m$有5个零点，则实数$m$的取值范围是 ___$(\frac{1}{2},\frac{3}{2})$___．