9. (2022•沈阳模拟)已知sinα=2sin(α+π2)\sin \alpha =\sqrt{2}\sin (\alpha +\frac{\pi }{2})sinα=2sin(α+2π),则sin2α−2sinαcosα+3cos4α=(\sin ^{2}\alpha -\sqrt{2}\sin \alpha \cos \alpha +3\cos ^{4}\alpha =(sin2α−2sinαcosα+3cos4α=( )))