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#6856967f-67d6-4db1-847b-e30a4b149ab8基础解答题等比数列的概念与通项数列

29. 已知正项等比数列{an}\{a_{n}\}满足条件a2a16=16a_{2}\cdot a_{16}=16a6+a7a3+a4=18\frac{{a}_{6}+{a}_{7}}{{a}_{3}+{a}_{4}}=\frac{1}{8}
(Ⅰ)求{an}\{a_{n}\}的通项公式;
(Ⅱ)设Tn=a1a2anT_{n}=a_{1}a_{2}\dotsb a_{n},求TnT_{n}的最大值.