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#6d73ab78-bdd5-4bbb-b8ca-9f2cf752163c简单解答题空间点线面基本关系立体几何

5. 在四棱柱ABCDA1B1C1D1ABCD-A_{1}B_{1}C_{1}D_{1}中,D1E=kD1A\overrightarrow{{D_1}E}=k\overrightarrow{{D_1}A}D1F=kD1B\overrightarrow{{D_1}F}=k\overrightarrow{{D_1}B}D1G=kD1C\overrightarrow{{D_1}G}=k\overrightarrow{{D_1}C}D1H=kD1D\overrightarrow{{D_1}H}=k\overrightarrow{{D_1}D}
(1)当k=34k=\frac{3}{4}时,试用AB,AD,AA1\overrightarrow{AB},\overrightarrow{AD},\overrightarrow{A{A_1}}表示AF\overrightarrow{AF}
(2)证明:EEFFGGHH四点共面;
(3)判断直线D1C1D_{1}C_{1}能否是平面D1ABD_{1}AB和平面D1DCD_{1}DC的交线,并说明理由.
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