18.已知函数f(x)=2(m+1)x2+4mx+2m−1f(x)=2(m+1)x^{2}+4mx+2m-1f(x)=2(m+1)x2+4mx+2m−1有一个零点在区间(0,1)(0,1)(0,1)内,则实数mmm的取值范围是 ___(−18(-\frac{1}{8}(−81[,]12)\frac{1}{2})21)___.