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#921993fd-84b6-419c-a0b3-305bc0148817基础解答题对数与对数函数函数

13.计算: (1)5log_53log311log1127+log82+log485^{\log \_{5}3}-\log _{3}11\cdot \log _{11}27+\log _{8}2+\log _{4}8

13.计算: (1)5log53log311log1127+log82+log485^{\log _{5}3}-\log _{3}11\cdot \log _{11}27+\log _{8}2+\log _{4}8; (2)若3m3m=233^{m}-3^{-m}=2\sqrt{3},求9m+9m9^{m}+9^{-m}的值.

解析
【解答】解:(1)原式=3log327+13log22+32log22=33+13+32=116=3-\log _{3}27+\frac{1}{3}lo{g}_{2}2+\frac{3}{2}lo{g}_{2}2=3-3+\frac{1}{3}+\frac{3}{2}=\frac{11}{6}. (2)3m3m=23\because 3^{m}-3^{-m}=2\sqrt{3}(3m3m)2=9m+9m2=12\therefore (3^{m}-3^{-m})^{2}=9^{m}+9^{-m}-2=129m+9m=14\therefore 9^{m}+9^{-m}=14