21.(2023•河南模拟)已知函数f(x)=(2x−3)e2−(ax+1)ex+2aex(a>0,a∈R)f(x)=(2x-3)e^{2}-(ax+1)e^{x}+2ae^{x}(a>0,a\in R)f(x)=(2x−3)e2−(ax+1)ex+2aex(a>0,a∈R),若存在唯一的整数x0x_{0}x0,使得f(x0)>0f(x_{0})>0f(x0)>0,则实数aaa的取值范围是 ___(1+e(1+e(1+e[,]1+3e22]\frac{1+3{e}^{2}}{2}]21+3e2]___.