20. 如图,在矩形ABCDABCDABCD中,AB=2AB=\sqrt{2}AB=2,BC=2BC=2BC=2,点EEE为BCBCBC的中点,点FFF在边CDCDCD上,若AB→⋅AF→=2\overrightarrow{AB}\cdot \overrightarrow{AF}=\sqrt{2}AB⋅AF=2,则AE→⋅BF→\overrightarrow{AE}\cdot \overrightarrow{BF}AE⋅BF的值是 .