22.已知函数y=x2−2(a+1)x−2y=x^{2}-2(a+1)x-2y=x2−2(a+1)x−2在区间[0[0[0,4]4]4]上是严格减函数,则实数aaa的取值范围是 ___{a∣a⩾3}\{a\vert a\geqslant 3\}{a∣a⩾3}___.