35．已知函数$f(x)=\left\{{\left.\begin{array}{l}{\frac{x-1}{x},x<t}\\ {{x^2}-x+1,t\leqslant x\leqslant 2}\end{array}\right.}\right.$，若$t=0$，则$f(x)$的值域是 ___$[\frac{3}{4}$[，]$+\infty )$___；若$f(x)$的值域是$[{\frac{3}{4},3}]$，则实数$t$的取值范围是 [　　]．