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#bf6e9c65-537b-4db7-b3ba-96aa718f1a08简单填空题等比数列的概念与通项数列

8. 已知等比数列{an}\{a_{n}\}的前nn项和为SnS_{n}2S3=a4a12S_{3}=a_{4}-a_{1},且a2+a4=15a_{2}+a_{4}=15,则a3+a5=(a_{3}+a_{5}=(  ))