9.如图,在ΔABC\Delta ABCΔABC中,向量AB→=3AD→\overrightarrow{AB}=3\overrightarrow{AD}AB=3AD,且CB→=λCA→+μCD→(λ,μ∈R)\overrightarrow{CB}=\lambda \overrightarrow{CA}+\mu \overrightarrow{CD}({\lambda ,\mu \in {R}})CB=λCA+μCD(λ,μ∈R),则λ+μ=\lambda +\mu =λ+μ=[ 1 ]{.underline}.