2.已知{an}\{a_{n}\}{an}是各项均为正整数的递增数列,且a1⩾3a_{1}\geqslant 3a1⩾3,若a1+a3+a5…+a2n−1=130a_{1}+a_{3}+a_{5}\ldots +a_{2n-1}=130a1+a3+a5…+a2n−1=130,则nnn的最大值为((( )))