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#03f118b6-f350-4486-8aaf-d73ef05e0883基础解答题同角三角函数关系三角函数与三角恒等变换

24.(2022秋•潮阳区期末)若sin(π6+α)=13\sin ({\frac{\pi }{6}+\alpha })=\frac{1}{3},则sin(5π6α)+cos(2π3+α)=\sin ({\frac{5\pi }{6}-\alpha })+\cos ({\frac{2\pi }{3}+\alpha })=[ 0 ].