29.在三棱柱ABC−A1B1C1ABC-A_{1}B_{1}C_{1}ABC−A1B1C1中,已知AA1⊥AA_{1}\botAA1⊥平面ABCABCABC,BC=3BC=3BC=3,AA1=8AA_{1}=8AA1=8,∠BAC=30∘\angle BAC=30\circ∠BAC=30∘,则该三棱柱外接球的表面积为 ___100π100\pi100π___.