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#58d5b0a0-28dc-4403-bf2b-46f06be2dc23简单解答题数列求和方法数列

18. 数列{an}\{a_{n}\}中,a1=2a_{1}=2an+1=an+n+1a_{n+1}=a_{n}+n+1
(1)求数列{an}\{a_{n}\}的通项公式;
(2)设bn=1an{b}_{n}=\frac{1}{{a}_{n}},数列{bn}\{b_{n}\}的前nn项和为TnT_{n},证明Tn<2T_{n}<2