35.(2023•北辰区三模)在ΔABC\Delta ABCΔABC中,BA→=a→\overrightarrow{BA}=\overrightarrow{a}BA=a,BC→=b→\overrightarrow{BC}=\overrightarrow{b}BC=b,若OOO为其重心,试用a→\overrightarrow{a}a,b→\overrightarrow{b}b表示BO→\overrightarrow{BO}BO为 ___13a→+13b→\frac{1}{3}\overrightarrow{a}+\frac{1}{3}\overrightarrow{b}31a+31b___;若OOO为其外心,满足ABBCBC→⋅BO→+BCABBA→⋅BO→=2m(BO→)2(m∈R)\frac{AB}{BC}\overrightarrow{BC}\cdot \overrightarrow{BO}+\frac{BC}{AB}\overrightarrow{BA}\cdot \overrightarrow{BO}=2m{(\overrightarrow{BO})}^{2}(m\in R)BCABBC⋅BO+ABBCBA⋅BO=2m(BO)2(m∈R),且sinA+sinC=2\sin A+\sin C=\sqrt{2}sinA+sinC=2,则mmm的最大值为 [ ]