22．（2023•重庆模拟）已知函数f(x)=ex−2ax−1f(x)=e^{x}-2ax-1f(x)=ex−2ax−1在区间(−1,1)(-1,1)(−1,1)内存在极值点，且f(x)<0f(x)<0f(x)<0在RRR上恰好有唯一整数解，则实数aaa的取值范围是 ___[14−14e2,12−12e)⋃(e−12,e2)[\frac{1}{4}-\frac{1}{4{e}^{2}},\frac{1}{2}-\frac{1}{2e})\bigcup (\frac{e-1}{2},\frac{e}{2})[41−4e21,21−2e1)⋃(2e−1,2e)___．