7.(2023•红河州一模)已知函数f(x)={1e∣lnx∣,x∈(0,+∞)ln(1−x),x∈(−∞,0)f(x)=\left\{\begin{array}{l}{\frac{1}{{e}^{\vert lnx\vert }},x\in (0,+\infty )}\\ {ln(1-x),x\in (-\infty ,0)}\end{array}\right.f(x)={e∣lnx∣1,x∈(0,+∞)ln(1−x),x∈(−∞,0),则下列说法正确的是((( )))