16.已知数列{an}\{a_{n}\}{an}满足an=1n+1+1n+2+1n+3+…+12na_{n}=\frac{1}{n+1}+\frac{1}{n+2}+\frac{1}{n+3}+\ldots +\frac{1}{2n}an=n+11+n+21+n+31+…+2n1.(1)数列{an}\{a_{n}\}{an}是递增数列还是递减数列?为什么?(2)证明:an⩾12a_{n}\geqslant \frac{1}{2}an⩾21对一切正整数恒成立.