12.(2022秋•潍坊月考)设函数f(x)=cos(ωx+π3)−12(ω>0)f(x)=\cos ({\omega x+\frac{\pi }{3}})-\frac{1}{2}({\omega >0})f(x)=cos(ωx+3π)−21(ω>0)在区间(0,π)(0,\pi )(0,π)恰有5个极值点,4个零点,则ω\omegaω的取值范围是((( )))