9.已知函数f(x)=xaf(x)=x^{a}f(x)=xa经过点(9,3)(9,3)(9,3),则不等式f(x2−x+1)<1f(x^{2}-x+1)<1f(x2−x+1)<1的解集为 ___(0,1)(0,1)(0,1)___.