6.已知函数f(x)={(3a−2)x+3,x⩽1logax+5a,x>1(a>0f(x)=\left\{\begin{array}{l}{(3a-2)x+3,}&{x\leqslant 1}\\ {lo{g}_{a}x+5a,}&{x>1}\end{array}\right.(a>0f(x)={(3a−2)x+3,logax+5a,x⩽1x>1(a>0且a≠1)a\ne 1)a=1)是RRR上的单调函数,则aaa的取值范围是((( )))