13. 设a>0a>0a>0且a≠1a\ne 1a=1,已知数列{bn}\{b_{n}\}{bn}满足bn={(3−a)n−2,n⩽6an−5,n>6{b_n}=\left\{{\left.\begin{array}{l}{(3-a)n-2,n\leqslant 6}\\ {{a^{n-5}},n>6}\end{array}\right.}\right.bn={(3−a)n−2,n⩽6an−5,n>6,且{bn}\{b_{n}\}{bn}是递增数列,则aaa的取值范围是 (2,3)(2,3)(2,3) .