11. (2023春•朝阳区校级月考)函数f(x)=cos(ωx+φ)(ω>0,∣φ∣<π2)f(x)=\cos (\omega x+\varphi )(\omega >0,\vert \varphi \vert <\frac{\pi }{2})f(x)=cos(ωx+φ)(ω>0,∣φ∣<2π)的部分图像如图所示.(1)求f(x)f(x)f(x)的解析式;(2)若∀x∈[−π4,π4]\forall x\in [-\frac{\pi }{4},\frac{\pi }{4}]∀x∈[−4π,4π],[f(x)]2−mf(x)−1⩽0[f(x)]^{2}-mf(x)-1\leqslant 0[f(x)]2−mf(x)−1⩽0,求mmm的取值范围.