14.(2023春•建华区校级月考)已知不等式aex(x+2)<x+1ae^{x}(x+2)<x+1aex(x+2)<x+1恰有1个整数解,则实数aaa的取值范围为 ___[23e,12)[\frac{2}{3e},\frac{1}{2})[3e2,21)___.