23.(2023春•图木舒克期末)已知函数f(x)=eax−2lnx−x2+axf(x)=e^{ax}-2lnx-x^{2}+axf(x)=eax−2lnx−x2+ax,若f(x)>0f(x)>0f(x)>0恒成立,则实数aaa的取值范围为 ___(2e,+∞)(\frac{2}{e},+\infty )(e2,+∞)___.