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#c9918c55-a9e6-4ca2-9a10-024f5c146613基础填空题函数的单调性函数

14.已知函数f(x)f(x)同时满足性质:①f(x)=f(x)f(-x)=-f(x);②对于x1\forall x_{1}x2(0,1)x_{2}\in (0,1)f(x1)f(x2)x1x2>0\frac{f({x}_{1})-f({x}_{2})}{{x}_{1}-{x}_{2}}>0,则函数f(x)f(x)可能是((  ))