31.(2023•亭湖区校级三模)已知函数f(x)=2asinax+acos(ax+π4)+b(a>0)f(x)=\sqrt{2}a\sin ax+a\cos (ax+\frac{\pi }{4})+b(a>0)f(x)=2asinax+acos(ax+4π)+b(a>0)的值域为[−1[-1[−1,3]3]3].(1)求f(x)f(x)f(x)的单调递增区间;(2)若f(ωx)(ω>0)f(\omega x)(\omega >0)f(ωx)(ω>0)在[0,π6][0,\frac{\pi }{6}][0,6π]上恰有一个零点,求ω\omegaω的取值范围.