2. 动点PPP与点F1(0,5)F_{1}(0,5)F1(0,5)与点F2(0,−5)F_{2}(0,-5)F2(0,−5)满足∣PF1∣−∣PF2∣=6\vert PF_{1}\vert -\vert PF_{2}\vert =6∣PF1∣−∣PF2∣=6,则点PPP的轨迹方程为___y29−x216=1(y⩽−3)\frac{{y}^{2}}{9}-\frac{{x}^{2}}{16}=1(y\leqslant -3)9y2−16x2=1(y⩽−3)___.