27.已知函数f(x)=2lnx−x2−mxf(x)=2lnx-x^{2}-mxf(x)=2lnx−x2−mx.(1)当m=0m=0m=0时,求函数f(x)f(x)f(x)的极值;(2)函数f(x)f(x)f(x)的图象与xxx轴交于两点A(x1A(x_{1}A(x1,0)0)0),B(x2B(x_{2}B(x2,0)0)0),B(x2B(x_{2}B(x2,0)0)0)且0<x1<x20<x_{1}<x_{2}0<x1<x2,证明:f′(13x1+23x2)<0f\prime (\frac{1}{3}x_1+\frac{2}{3}x_2)<0f′(31x1+32x2)<0.