25.(2023•攀枝花一模)若函数f(x)=sin(2ωx+π3)(ω>0)f(x)=\sin ({2\omega x+\frac{\pi }{3}})(\omega >0)f(x)=sin(2ωx+3π)(ω>0)在(π2,π)({\frac{\pi }{2},\pi })(2π,π)上单调,且在(0,π4)({0,\frac{\pi }{4}})(0,4π)上存在极值点,则ω\omegaω的取值范围为 ___(13,712]({\frac{1}{3},\frac{7}{12}}](31,127]___.