28.已知函数f(x)=ex+2ax−1f(x)=e^{x}+2ax-1f(x)=ex+2ax−1,其中aaa为实数,eee为自然对数底数,e=2.71828…e=2.71828\ldotse=2.71828….(1)已知函数x∈Rx\in Rx∈R,f(x)>0f(x)>0f(x)>0,求实数aaa取值的集合;(2)已知函数F(x)=f(x)−ax2F(x)=f(x)-ax^{2}F(x)=f(x)−ax2有两个不同极值点x1x_{1}x1、x2x_{2}x2.①求实数aaa的取值范围;②证明:2a(x1+x2)>3x1x22\sqrt{a}(x_{1}+x_{2})>3x_{1}x_{2}2a(x1+x2)>3x1x2.