16．已知函数f(x)=ex−ax−1(a∈R)f(x)=e^{x}-ax-1(a\in R)f(x)=ex−ax−1(a∈R)．（1）求曲线y=f(x)y=f(x)y=f(x)在点(0(0(0，f(0))f(0))f(0))处的切线方程；（2）讨论函数f(x)f(x)f(x)的单调性；（3）判断e0.01e^{0.01}e0.01与1.01的大小关系，并说明理由．