26.(1)已知函数f(x)=logax(a>0f(x)=\log _{a}x(a>0f(x)=logax(a>0且a≠1)a\ne 1)a=1),若f(x)f(x)f(x)在区间[a[a[a,2a]2a]2a]上的最大值与最小值之差为1,求aaa的值;(2)若a>0a>0a>0,解关于xxx的不等式log13(−ax−1)>log13(a−x2){\log _{\frac{1}{3}}}(-ax-1)>{\log _{\frac{1}{3}}}({a-{x^2}})log31(−ax−1)>log31(a−x2).