10.若数列{an}\{a_{n}\}{an}满足a1=−3a_{1}=-3a1=−3,an+1=1+an1−ana_{n+1}=\frac{1+{a_n}}{1-{a_n}}an+1=1−an1+an,则a2022a_{2022}a2022的值为((( )))