10.设函数f(x)f(x)f(x)的定义域为RRR,f(x+1)f(x+1)f(x+1)为奇函数,f(x+2)f(x+2)f(x+2)为偶函数,当x∈[1x\in [1x∈[1,2]2]2]时,f(x)=ax2+bf(x)=ax^{2}+bf(x)=ax2+b.若f(0)+ff(0)+ff(0)+f(3)=6=6=6,则f(92)=f(\frac{9}{2})=f(29)=___52\frac{5}{2}25___.