28.(2023•包头一模)已知函数f(x)=aex−ln(x+1)−1(a⩾1)f(x)=ae^{x}-ln(x+1)-1(a\geqslant 1)f(x)=aex−ln(x+1)−1(a⩾1).(1)当a=ea=ea=e时,求曲线y=f(x)y=f(x)y=f(x)在点(0(0(0,f(0))f(0))f(0))处的切线与两坐标轴所围成三角形的面积;(2)若f(x)f(x)f(x)没有零点,求aaa的取值范围.