4．数列{an}\{a_{n}\}{an}满足a1+3a2+32a3+⋯+3n−1an=n3(n∈N∗)a_{1}+3a_{2}+3^{2}a_{3}+\dotsb +3^{n-1}a_{n}=\frac{n}{3}({n\in {N^*}})a1+3a2+32a3+⋯+3n−1an=3n(n∈N∗)，则a1a2a3⋯a10a_{1}a_{2}a_{3}\dotsb a_{10}a1a2a3⋯a10等于((( )))