41. 设函数f(x)f(x)f(x)的定义域为RRR,f(x)f(x)f(x)为偶函数,f(x+1)f(x+1)f(x+1)为奇函数,当x∈[1x\in [1x∈[1,2]2]2]时,f(x)=a⋅2x+bf(x)=a\cdot 2^{x}+bf(x)=a⋅2x+b,若f(0)+ff(0)+ff(0)+f(1)=−4=-4=−4,则f(72)=f(\frac{7}{2})=f(27)=___4−424-4\sqrt{2}4−42___.