32. 若函数f(x)=loga(x3−ax)(a>0f(x)=\log _{a}(x^{3}-ax)(a>0f(x)=loga(x3−ax)(a>0且a≠1)a\ne 1)a=1)在区间(−14(-\frac{1}{4}(−41，0)0)0)内单调递增，则实数aaa的取值范围是((( )))