24. 在三棱柱ABC−A1B1C1ABC-A_{1}B_{1}C_{1}ABC−A1B1C1中，DDD为BB1BB_{1}BB1的中点，22AA1=AB=BC\frac{\sqrt{2}}{2}A{A}_{1}=AB=BC22AA1=AB=BC，AA1⊥AA_{1}\botAA1⊥平面ABCABCABC，∠ABC=90∘\angle ABC=90\circ∠ABC=90∘，则下列结论错误的是((( )))